In a DeltaABC, if 2AC=3CB, then 2OA+3OB ...

In a `DeltaABC`, if 2AC=3CB, then 2OA+3OB is equal to

A

5OC

B

`-OC`

C

`OC`

D

none of these

Verified by Experts

The correct Answer is:

A

`2OA+3OB=2(OC+CA)+3(OC+CB)`
`=5OC+2CA+3CB=5OC(because2CA=-3CB)`.

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