Home
Class 12
MATHS
Five points given by A,B,C,D and E are i...

Five points given by A,B,C,D and E are in a plane. Three forces AC,AD and AE act at A annd three forces CB,DB and EB act B. then, their resultant is

A

2AC

B

3AB

C

3DB

D

2BC

Text Solution

Verified by Experts

The correct Answer is:
B
Points `A,B,C,D and E` are in a plane.
Resultant`=(AC+AD+AE)+(CB+BD+EB)`
`=(AC+CB)+(AD+DB)+(AE+EB)`
`=AB+AB+AB=3AB`
Promotional Banner

Similar Questions

Explore conceptually related problems

ABCDE is a pentagon. Forces AB,AE,DC and ED act at a point. Which force should be added to this systemm to make the resultant 2AC?

Consider the regular hexagon ABCDEF with centre at O (origin). Q. Five forces AB,AC,AD,AE,AF act at the vertex A of a regular hexagon ABCDEF. Then, their resultant is (a)3AO (b)2AO (c)4AO (d)6AO

In the given figure AC,CE and EH are tangents drawn to the circle at B,D and F respectively.IF CB=5 cm.and EF=3 cm,then the length of CE is:

The magnitudes of mutually perpendicular forces a,b and c are 2,10 and 11 respectively. Then the magnitude of its resultant is

Two equal forces (P each) act at a point inclined to cach other at an angle of 120^(@) . The magnitude of their resultant is

In the given diagram name the parts A, B, C and D and E .

There are five points A,B,C,D and E. no three points are collinear and no four are concyclic. If the line AB intersects of the circles drawn through the five points. The number of points of intersection on the line apart from A and B is

A, B and C are three elements giving compounds AB, AC , and BC. AB contains 75% of A, AC contains 57.14% of C and BC contains 11.11% of B . Show that the result illustrate the law of reciprocal proportions.

In Delta ABC , D and E are points in the sides AB and AC respectively such that DE || BC If AD = 6 cm , DB = 9 cm , and AE = 8 cm find AC.

If A,B,C are three points on a line and B lies between A and C, then prove that AC-AB = BC