If the resultant of three forces vecF1= ...

If the resultant of three forces `vecF_1= phati +3hatj-hatk , vecF_2 =-5hati+hatj+2hatk and vecF_3= 6hati -hatk` acting on a particle has a magnitude equal to 5 units, then what is difference in the values of `p` ?

A

`-6`

B

`-4`

C

`2`

D

4

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The correct Answer is:

B, C

Let R be the resultant. Then
`R=F_(1)+F_(2)+F_(3)=(p+1)hati+4hatj`
Given, `|R|=5`. Therefore, `(p+1)^(2)+16=25`.
or `p+1=+-3` or `p=2,-4`.

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