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If points hati+hatj, hati -hatj and p ha...

If points `hati+hatj, hati -hatj and p hati +qhatj+rhatk` are collinear, then

A

p=1

B

r=0

C

`q in R`

D

`q ne 1`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D
Points `A(hati+hatj),B(hati-hatj) and C(phati+qhatj+rhatk)` are collinear
Now, `AB=-2hatj`
and `BC=(p-1)hati+(q+1)hatj+rhatk`
Vectors AB and BC must be collinear
`implies p=1,r=0 and q ne -1`
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