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If first term of a GP is a, third term i...

If first term of a GP is a, third term is b and `(n+1)th` term is c. The `(2n+1)th` term of a GP is

A

`csqrt((b)/(a))`

B

`(bc)/(a)`

C

`abc`

D

`(c^(2))/(a)`

Text Solution

Verified by Experts

Let common ratio =r
` therefore b=ar^(2) implies r=sqrt((b)/(a))`
Also, `c=ar^(n) implies r^(n)=(c)/(a)`
`therefore t_(2n+1)= ar^(2n)=a(r^(n))^(2)=a((c)/(a))^(2)=(c^(2))/(a)`
Hence, (d) is the correct answer.
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