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If sum of the mth powers of first n odd ...

If sum of the mth powers of first n odd numbers is `lambda,Aamgt1`, then

A

`lambdaltn^(m)`

B

`lambdagtn^(m)`

C

`lambdaltn^(m+1)`

D

`lambdagtn^(m+1)`

Text Solution

Verified by Experts

The correct Answer is:
D

`:.mgt1`
`:.(1^(m)+3^(m)+5^(m)+"..."+(2n-1)^(m))/(n)gt((1+3+5+"..."+(2n-1))/(n))^(m)`
`=(((n)/(2)(1+2n-1))/(n))^(m)=n^(m)`
`:.1^(m)+3^(m)+5^(m)+"..."+(2n-1)^(m)gtn^(m+1)`
Hence, `lambdagtn^(m+1)`
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