Home
Class 12
MATHS
In a sequence of 21 terms the first 11 t...

In a sequence of 21 terms the first 11 terms are in A.P. with common difference 2. and the last 11 terms are in G.P. with common ratio 2. If the middle tem of the A.P. is equal to the middle term of the G.P., then the middle term of the entire sequence is

A

`-(10)/(31)`

B

` (10)/(31)`

C

`-(32)/(31)`

D

`(32)/(31)`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

What is the common difference between the consecutive terms of an A.P.

If 9 times the 9th term of an A.P. is equal to 13 times the 13^(th) term, then 22nd term of the A.P. is :

In an AP, the seventh term is 4 and the common difference is -4. Which is the first term?

If the sum of first p terms of an A.P is equal to the sum of the first q terms , then find the first (p+q) terms .

In the A.P., the common difference is 3, first term is 1, then its tenth term is:

7th term of an A.P. is 40. then the sum of the first 13 terms is

The sum of the first 8 terms of an A.P. is 100 and the sum of its first 19 terms is 551. Find the first term and the common difference of the AP.

The first term of a G.P. is 1. The sum of the third term and fifth term is 90. Find the common ratio of G.P.

If the 2nd , 5th and 9th terms of a non-constant A.P are in G.P then the common ratio of this G.P is

The first term of a G.P . Is and the sum of 3^(rd) and 5^(th) terms is 90 . Find the common ratio of the G.P.