If x=log(2a)((bcd)/2), y=log(3b)((acd)/3...

If `x=log_(2a)((bcd)/2), y=log_(3b)((acd)/3), z=log_(4c)((abd)/4) and w=log_(5d)((abc)/5)` and `1/(x+1)+1/(y+1)+1/(z+1)+1/(w+1) = log_(abcd)N+1,` then value of `N/40` is

A

40

B

80

C

120

D

160

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The correct Answer is:

A, B, C

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