Given that log2(3)=a,log3(5)=b,log7(2)=c...

Given that `log_2(3)=a,log_3(5)=b,log_7(2)=c`, express the logorithm of the number 63 to the base 140 in terms of a,b & c.

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The correct Answer is:

`=((2ac+1)/(2c+abc+1))`

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