If (lna)/(b-c)=(lnb)/(c-a)=(lnc)/(a-b), ...

If `(lna)/(b-c)=(lnb)/(c-a)=(lnc)/(a-b)`, prove the following .
`a^(b^2+bc+c^2).b^(c^2+ca+a^2).c^(a^2+ab+b^2)=1`

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The correct Answer is:

`therefore` `a^(b^2+bc+c^2).b^(c^2+ca+a^2).c^(a^2+ab+b^2)=1`

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