If {:A=[(0,1,-1),(2,1,3),(3,2,1)]:} then...

If `{:A=[(0,1,-1),(2,1,3),(3,2,1)]:}` then `(A(adj A)A^(-1))A=`

A

`[{:(-6,0,0),(0,-6,0),(0,0,-6):}]`

B

`[{:(0,(1)/(6),-(1)/(6)),((1)/(3),(1)/(6),(1)/(2)),((1)/(2),(1)/(3),(1)/(6)):}]`

C

`[{:(3,0,0),(0,3,0),(0,0,3):}]`

D

`[{:(1,0,0),(0,1,0),(0,0,1):}]`

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The correct Answer is:

C

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