Home
Class 12
MATHS
Let S be the set of the first 21 natural...

Let S be the set of the first 21 natural numbers, then the probability of
Choosing `{x,y,z}subeS`, such that x,y,z are not consecutive is,

A

`(17)/(70)`

B

`(34)/(70)`

C

`(51)/(70)`

D

`(34)/(35)`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

Let S be the set of the first 21 natural numbers, then the probability of Choosing {x,y,z}subeS , such that x,y,z are in AP, is

Let S be the set of the first 21 natural numbers, then the probability of choosing {x, y}inS , such that x^3+y^3 is divisible by 3, is

A natural number x is chosen at random from the first 100 natural number. The probability that x+100/x gt 50 is

The number of three digit numbers of the form xyz such that x lt y , z le y and x ne0 , is

Let all the elements of the following sets: A={x:x"is an odd natural number"}

If A = (x: x = (1)/(y), y in N ), where N is the set of natural numbers , then

Let x,y,z be three positive prime numbers. The progression in which sqrt( x) , sqrt( y ) , sqrt( z) can be three terms ( not necessarily consecutive ) is :

If [1X 2Y 6Z] is a number divisible by 9,then the least value of X+Y+Z is:

Let A be a set of n (>=3) distinct elements. The number of triplets (x, y, z) of the A elements in which at least two coordinates is equal to

Find the total number of positive integral solutions for (x ,y ,z) such that x y z=24. Also find out the total number of integral solutions.