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A chess game between Kamsky and Anand is...

A chess game between Kamsky and Anand is won by whoever first wins a out of 2 games. Kamsky's chance of winnig, drawing or lossing a particular game are 2. The games are independent and `p+q +r=1`. Prove that the probability that Kamsky wins the match is `(p^2(P+3r))/((p+r)^3)`.

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The correct Answer is:
(b)
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