Draw the curve `y=e^(x)`

The equation of the horizontal tangent to the curve y=e^(x)+e^(-x) is :

A point of infection of the curve y = e^(-x2) is

The tangent drawn at the point (0,1) on the curve y = e^(2x) meets x-axis at the point

The tangent to the curve y = e^(2x) at the point (0,1) meets x-axis at

The slopes of the tangent and normal at (0, 1) for the curve y=sinx+e^(x) are respectively :

A point of inflection of the curve y = e^(-x^(2)) is

The area enclosed between the curve y=log_e(x+e) and the coordinate axes is :

The line (x)/(a)+(y)/(b)=1 touches the curves y= be^(-x//a) at the point :

The particle moves along the curve y=x^(2)+2x Then the point on the curve such that x and y coordiantes of the particle change with the same rate