The equation `2 "cos"^(2)((x)/(2))"sin"^(2) x = x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2)` has no real solution more than one solution none of these

Find the general solution of the equation sin2x+cos x=0 .

The number of real solution of the equation x^(2)=1-|x-5| is:

The number of solutions for the equation sin2x+cos 4x=2 is

Solution of the inequation (x+5)/(x-2) le 0 is

Number of solutions of the equation cos^(4) 2x+2 sin^(2) 2x =17 (cos x + sin x)^(8), 0 lt x lt 2 pi is

The solution set of |x^(2)-8|le 8 is

If cos x- sin x ge 1 and 0 le x le 2pi , then find the solution set for x .

The solution set of the equation (5 x+8)/(4-x)le 2

Find the solution of the equation ( sin x + cos x ) sin 2 x =a(sin^(3) x + cos^(3) x) located between (pi)/(2) and pi and for which values of 'a' does this equation have at most one solution satisfying the condition (pi)/(2) le x le pi .

Let (b cos x)/(2 cos 2x-1)=(b + sin x)/((cos^(2) x-3 sin^(2) x) tan x), b in R . Equation has solutions if