Find the quadrants of the coordinate pla...

Find the quadrants of the coordinate planes such that for each point `(x,y)` on these quadrants ( where ` x ne 0 , y ne 0`) , the equation, ` (sin^(4) theta )/x + ( cos^4 theta)/( y)=(1)/(x+y) ` is soluble for ` theta ` .

Verified by Experts

The correct Answer is:

`rArr` x and y must be same sign, which is true in ist and 3rd quadrant only.

Similar Questions

Explore conceptually related problems

State True or False, if 'false' write correct statement. The point (-x,-y) lies in the first quadrant where x lt 0, y lt 0 .

If x = a(cos theta + theta sin theta), y = a (sin theta - theta cos theta), (dy)/(dx) =

Find (dy)/(dx)," if "x= a(theta+ sin theta), y= a(1- cos theta) .

x = a cos theta, y = b sin theta .

Find the area of the region bounded by x^(2)=4y,y=2,y=4 and the y-axis in the first quadrant.

The locus of the point x=a cos theta, y=b sin theta is

Find the area of the circle whose parametric equations x=3+2 cos theta and y=1+2 sin theta.

If x = a(cos theta + theta sin theta), y = a (sintheta - theta cos theta), dy/dx =

If x=a cos ^(3) theta and y = a sin^(3) theta then (dy)/( dx) =