Find the number of solutions of `sin^2x-sinx-1=0in[-2pi,2pi]`

Verified by Experts

The correct Answer is:

4

Similar Questions

Explore conceptually related problems

Find the number of solutions of 2cos x=|sinx| when x in [0,4pi] .

Find the number of solutions of sin^(2) x cos^(2)x=1+cos^(2)x+sin^(4) x in the interval [0,pi]

Find the number of solutions of the equation sinx=x^2+x+1.

Find the number of solution of tan x + sec x =2 cos x in [0,2pi]

The number of solutions of tanx-m x=0,m >1, in (-pi/2, pi/2) is

Find the number of solutions of |cos x|=sin x , 0 le x le 4 pi

Find the number of solution of the equations 2^(cos x)=|sin x|, when x in[-2pi,2pi]

The total number of solutions of cos x= sqrt(1- sin 2x) in [0, 2pi] is equal to

Find the number of solution of the equations x+ 2 tan x =(pi)/(2) , when x in[0,2pi]

Find the number of solutions of cos x =|1+ sin x |, 0 le x le 3 pi