If : cot theta + cot((pi)/4 + theta) = 2...

If `: cot theta + cot((pi)/4 + theta) = 2`, then : `theta` =

A

`2 n pi pm(pi)/(6)`

B

`2n pi pm (pi)/3`

C

`npi pm (pi)/3`

D

`npi pm (pi)/6`

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The correct Answer is:

D

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