Consider a quadratic equation az^(2)+bz+...

Consider a quadratic equation `az^(2)+bz+c=0,` where a,b and c are complex numbers.
The condition that the equation has one purely real root, is

A

`(a barc-cbara)^(2)=(b barc-barbc) (abarb-barab)`

B

`(cbara-barca)^(2)=(abarb+barab)(b barc+barbc)`

C

`(cbara+barca)^(2)=(abarb-barab)(b barc-barbc)`

D

`(cbara-barca)^(2)=(abarb+barab)(b barc-barbc)`

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The correct Answer is:

b

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