If z^3+(3+2i)z+(-1+i a)=0 has one real r...

If `z^3+(3+2i)z+(-1+i a)=0` has one real roots, then the value of `a` lies in the interval `(a in R)`

A

(-2,1)

B

(-1,0)

C

(0,1)

D

(-2,3)

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The correct Answer is:

A, B, D

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