If |[a,b-c,c+b],[a+c,b,c-a],[a-b,a+b,c]|...

If `|[a,b-c,c+b],[a+c,b,c-a],[a-b,a+b,c]|=0` , then the line `a x+b y+c=0` posses through the fixed point which is

A

(1,2)

B

(1,1)

C

(-2,1)

D

(1,0)

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The correct Answer is:

B

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