Home
Class 12
MATHS
A line O P through origin O is inclined ...

A line `O P` through origin `O` is inclined at `30^0 and 45^0` to `OX and O Y ,` respectivley. Then find the angle at which it is inclined to `O Zdot`

Text Solution

Verified by Experts

The correct Answer is:
`r=|r|(pm(1)/(sqrt(3))hat(i)pm(1)/(sqrt(3))hat(j)pm(1)/(sqrt(3))hat(k))`
Promotional Banner

Similar Questions

Explore conceptually related problems

A straight line through the origin O meets the parallel lines 4x+2y=9 and 2x+y+6=0 at points P and Q respectively. Then the point O divides the segment PQ in the ratio :

A vector makes angles 45^(o) and 60^(o) with positive axes of x and y respectively. Then the angle between the vector and the z-axis is

A line passing through P(4, 2) meets the x and y-axis at A and B respectively. If O is the origin, then locus of the centre of the circumcircle of DeltaOAB is :

A line passing through P(3,4) meets the x -axis and y -axis at A and B respectively. If O is the origin, then locus of the centre of the circum centre of Delta O A B is

A vector vec r is inclined at equal angles to O X, OY and OZ. If the magnitude of vec r is 6 units, then vec r =

A line which makes angle 60^(o) with y -axis and z-axis, then the angle which it makes with x -axis is

The combined equation to a pair of lines passing through the origin and inclined 30^(circ) and 60^(circ) respectively with x -axis is

A tower leans towards North. At two points due south of it and at distances a and b metres respectively from its foot, the angles of elevation of the top of the tower are found to be a and B. If is the angle of inclination of the tower to the horizontal, then cot O is equal to :

A block slides down a rough inclined plane of inclination 45^(@) . If the coefficent of kinetic friction is 0.5 , find the acceleration of the sliding block . (g=10ms^(-2)) .