Find the equation of plane which passes ...

Find the equation of plane which passes through the point `(1, 2,0)` and which is perpendicular to the plane `x-y+z=3 and 2x+y-z+4=0`.

Verified by Experts

The correct Answer is:

`y+z=2`

Similar Questions

Explore conceptually related problems

Equation of the plane passing through the point (1,1,1) and perpendicular to each of the planes x+ 2y+3z-7=0 and 2x-3 y+4 z=0 is

Equation of the plane passing through (1,1,1) and (1,-1,-1) and perpendicular to 2x-y+z+5=0 is

The plane passing through the point (a, b, c) and parallel to the plane x + y + z = 0 is:

Equation of the plane passing through the points (3,-1,2) and (2,2,-1) and parallel to the z -axis is

Find the equation of the plane passing through the line of intersection of the planes .x+ y+ z = 6 and 2x+ 3y+ 4z-5 = 0 and the point (1,1,1).

Equation of line passing through the point (2,3,1) and parallel to the line of intersection of the plane x-2y - z +5 =0 and x+y+3z = 6 is

Equatin of line passing through the point (2,3,1) and parallel to the line of intersection of the planes x−2y−z+6=0 and x+y+3z=5 is

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 .