Find the value of lambda for which the p...

Find the value of `lambda` for which the plane `x+y+z=sqrt(3)lambda` touches the sphere `x^2+y^2+z^2-2x-2y-2z=6.`

Verified by Experts

The correct Answer is:

`lambda=sqrt(3)pm3`

Similar Questions

Explore conceptually related problems

For what value of lambda does the line y=2x+lambda touches the hyperbola 16x^(2)-9y^(2)=144 ?

Find the centre and radius of the sphere 2x^2+2y^2+2z^2-2x-4y+2z+3=0 .

If the line y=2x+lambda touches the hyperbola 9x^(2)-5y^(2)=45 , then lambda =

The line 4y - 3x + lambda =0 touches the circle x^2 + y^2 - 4x - 8y - 5 = 0 then lambda=

Find the value of lambda , such that the line (x-2)/(6)=(y-1)/(lambda) = (z+5)/(-4) is perpendicular to the plane 3x - y - 2z = 7 .

Find the distance of the point (-6,0,0) from the plane 2x-3y+6z = 2 .

Find the distance of the point (-6, 0, 0) from the plane 2x - 3y + 6z = 2.

Find the angle between two planes 2x+y-5z=0 and 4x -3y+7z=0

Find the distance of the point (3,-2,1) from the plane 2x-y+2z+3=0.