Home
Class 12
MATHS
P(0, 3, -2), Q(3, 7, -1) and R(1, -3, -1...

`P(0, 3, -2), Q(3, 7, -1) and R(1, -3, -1)` are 3 given points. Find `vec (PQ)`

Text Solution

Verified by Experts

The correct Answer is:
`(A) to r (B) to q, (C) to p D to s`
Promotional Banner

Similar Questions

Explore conceptually related problems

Show that the points P(- 2 , 3, 5) , Q (1, 2, 3) and R(7, 0, -1) are collinear.

If P=(1,0), Q=(-1,0) and R=(2,0) are three given points, then the locus of S satisfying the relation S Q^(2)+S R^(2)=2 S P^(2) is

Let P-=(-1, Q), Q-=(0, 0) and R-=(3, 3sqrt(3)) be three points. The equation of the bisector of the angle PQR is :

Let P(-1, 0), Q(0, 0) and R(3, 3sqrt(3)) be three points. Then the equation of the bisector of the angle PQR is :

The points P(2,3) , Q(3, 5), R(7, 7) and S(4, 5) are such that:

Show that the points A (-2, 3, 5), B(1, 2, 3) and C(7, 0, -1) are collinear.

If A=[(1,2,3),(2,3,1)] and B=[(3,-1,3),(-1,0,2)] , then find 2A-B .

Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0) . Let z=px+qy , where p, q gt 0 . Condition on p and q so that the minimum of z occurs at (3, 0) and (1, 1) is

Let P-=(-1,0),Q-=(0,0) and R-=(3,3sqrt(3)) be three points. The equation of the bisector of the angle PQR is