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Find dy/dx if x-3y=x^2...

Find `dy/dx if x-3y=x^2`

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The correct Answer is:
(a) `f(2x) = {{:(2x - [2x]",",2x !in I),(1",",2x in I):}`
(b) Domain of `g(g(x)) in R` and Range of `g(g(x)) in {0}`
(c) Here, f(2x) and g(x) are periodic with period 1/2 and 1 also g{g(x)} is constant function.
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