Find the differential equation of `xy = ae^x + be^(-x)`.

Form the differential equation of family of curces y= ae^(2x) +be^(-2x) by eliminating the arbitary constants a & b.

The general solution of the differential equation dy/dx = e^(x^(2)/2)+xy is

Find the general solution of the differential equation y dx - (x + 2y^(2))dy = 0 .

Find the general solution of the differential equation x(dy)/(dx)+ 2y= x^(2) (x ne 0)

Find the general solution of the differential equation x (dy)/(dx) + 2y = x^(3)(x ne 0) .

Find the equation of the curve passing through the point (1,1) whose differential equation is x dy = (x^(2) - 1) dx(x ne 0) .

Find the particular solution of the differential equation : x^(2)dy = y(x+y)dx = 0 , when x = 1, y = 1.

Find the particular solution of the differential equation : x e^(y//x) - y sin.((y)/(x)) + x.(dy)/(dx) sin((y)/(x)) = 0 For x = 1, y = 0