If asin^(-1)x-bcos^(-1)x=c , then asin^(...

If `asin^(-1)x-bcos^(-1)x=c ,` then `asin^(-1)x+bcos^(-1)x` is equal to

A

0

B

`( pi ab + c(b-a))/(a+b)`

C

`pi/2`

D

`(pi ab + c(a -b))/(a +b)`

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The correct Answer is:

D

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