Let f : R to [0, pi/2) be defined by f ...

Let `f : R to [0, pi/2)` be defined by `f ( x) = tan^(-1) ( 3x^(2) + 6x + a)". If " f(x)` is an onto function . then the value of a is

A

1

B

2

C

3

D

4

Verified by Experts

The correct Answer is:

C

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