If p is the length of perpendicular from origin to the line whose intercepts on the axes are 'a' and 'b' then prove that `(1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2))` .

If p is the length of the perpendicular from the origin on the line whose intercepts on the axes are a and b, then

If p is the length of perpendicular from the origin to the line whose intercepts on the axes are a and b, then show that 1/p^(2) = 1/a^(2) + 1/b^(2) .

The tangent of angle between the lines whose intercepts on the axes are a,-b and b,-a respectively, is

If p and q are the lengths of perpendicular from the origin to the lines x cos theta-y sin theta=k cos 2theta and x sec theta+y "cosec" theta=k respectively, prove that p^(2)+4q^(2)=k^(2) .

ABC is a right triangle right angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB. Prove that (i) pc = ab (ii) (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2)) .

If P is the length of perpendicluar drawn from the origin to any normal to the ellipse x^(2)/25+y^(2)/16=1 , then the maximum value of p is

If cosec theta+cottheta=p ,then prove that: cos theta=(p^(2)-1)/(p^(2)+1)

Derive the expression for the length of the perpendicular drawn from the point (x_1,y_1) yo the line ax + by + c=0

Find the product of the perpendiculars drawn from the point (x_1,y_1) on the lines ax^2+2hxy+by^2=0

The coordinate axes are rotated about the origin O in the counter clockwise direction through an angle 60^(circ) . If p and q are the intercepts made on the new axes by a line whose equation referred to the original axes is x+y=1 then (1)/(p^(2))+(1)/(q^(2))=