Prove that the parallelogram formed by the lines `x/a+y/b=1,x/b+y/a=1,x/a+y/b=2 a n d x/b+y/a=2` is a rhombus.

The area of the triangle formed by the lines x^(2 )+4 x y+y^(2)=0, x+y=1 is

The lines a x+b y=c, b x+c y=a and c x+a y=b are concurrent, if

The incentre of the triangle formed by (x)/(a)+(y)/(b)=1 is

Area of the parallelogram formed by 2 x^(2)+5 x y+3 y^(2)=0 and 2 x^(2)+5 x y+3 y^(2)+3 x+4 y+1=0 is

If a, h, b are in A.P. then the triangular area formed by the pair of lines a x^(2)+2 h x y+b y^(2)=0 and the line x-y=-2 is, in square units

Orthocentre of the triangle formed by the lines x+y+1=0 and 2x^(2)+y^(2)+x+2y-1=0 is

Orthocentre of the triangle formed by the lines x+y+1=0 and 2 x^(2)-x y-y^(2)+x+2 y-1=0 is

The lines y=mx, y+2x=0, y=2x+k and y+mx=k form a rhombus if m is equal to :

Find the area of the smaller region bounded by the ellipse x^(2)/a^(2) + y^(2)/b^(2) =1 and the line x/a + y/b =1 .

The area between x^2/a^2+y^2/b^2 =1 and st.line x/a+y/b=1 is : x