Calculate the length of the perpendicular from (5, 1) to the straight line 5 x + 12 y − 9 = 0.

Foot of the perpendicular from (-2,-1) on to the line 3 x+2 y-5=0 is

The length of the perpendicular from the origin to the plane 3x+4y+12z ne 52 is

The product of the perpendiculars from (1, 1) to the pair of lines x^(2)+4 x y+3 y^(2)=0 is

The product of the perpendiculars from (-1,2) to the pair of-lines 2 x^(2)-5 x y+2 y^(2)=0 is

Foot of perpendicular drawn from (0, 5) on the line 3x-4y-5=0 is :

Derive the expression for the length of the perpendicular drawn from the point (x_1,y_1) yo the line ax + by + c=0

Find the coordinates of the foot of the perpendicular from the point (-1,3) to the line 3x-4y-16=0.

The length of the tangent from (5, 1) to the circle x^2+y^2+6x-4y-3=0 is :

Find the co-ordinates of the foot of the perpendicular from the point (-1,3) to the line 3x - 4y - 16 = 0