Home
Class 12
MATHS
Discuss the position of the points (1,2)...

Discuss the position of the points (1,2) and (6,0) with respect to the circle `x^2+y^2-4x+2y-11=0`

Text Solution

Verified by Experts

The correct Answer is:
Hence, the point (1,2) lies inside the circle and the point (6,0) lies outside the circle.
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the power of point (2,4) with respect to the circle x^(2)+y^(2)-6x+4y-8=0

Find the position of the point (-2,2) with respect to the parabola y^2-4y+9x+13=0 .

Find the centre of the circle 3x^2+3y^2-6x-12y-2=0

Which of the statements in the following is false in respect of the conic x^(2)-3 y^(2)-4 x-6 y-11=0 ?

The least and the greatest distances of the point (10 , 7) from the circle x^(2) + y^(2) - 4x - 2y - 20 = 0 are

The greatest distance of the point P(10, 7) form the circle x^(2)+y^(2)-4x-2y-20=0 is :

Find the equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0, x^2 + y^2 + 2x - 4y -6 = 0 and with its centre on the line y = x.

The point diametrically opposite to the point P (1, 0) on the circle x^2+y^2+2x+4y-3=0 is :

Find the equation of the circle passing through the points of intersection of the circles x^2 + y^2 - 2x - 4y - 4 = 0 and x^2 + y^2 - 10x - 12y +40 = 0 and whose radius is 4.

The equation of the circle having its centre on the line x +2y - 3 = 0 and passing through the points of intersection of the circles x^2 + y^2 - 2x - 4y +1 = 0 and x^2+y^2 -4x -2y +4=0 is :