Find the equation of the chord of x^(2)+...

Find the equation of the chord of `x^(2)+y^(2)-6x+10y-9=0` which is bisected at (-2,4)

Verified by Experts

The correct Answer is:

5x=9y+46=0

Similar Questions

Explore conceptually related problems

Find the equation of that chord of the circle x^2 + y^2 = 15, which is bisected at the point (3,2)

The equation of the chord of parabola y^(2)=8 x which is bisected at the point (2,-3) is

Equation of the chord of the hyperbola 25 x^(2)-16 y^(2)=400, which is bisected at the point (6,2) is

The equation of the chord of the circle x^(2)+y^(2)-2 x-4 y-20=0 whose mid point is (1,3) is

The chord of the circle x^(2)+y^(2)-y^(2)-4x=0 which is bisected at (1,0) is perpendicular to the line

The equation of the normal to the circle x^(2)+y^(2)+6 x+4 y-3=0 at (1,-2) is

Find the centre of the circle 3x^2+3y^2-6x-12y-2=0

Find the equation of the tagent to the hyperbola x^(2)-4y^(2)=36 which is perpendicular to the line x-y+4=0 .

The equation of the chord of the circle x^2 + y^2 - 4x = 0 , whose mid-point is (1, 0) is :

Find the equation of the normal to the parabola y^2=4x which is perpendicular to the line 2x+6y+5=0.