Find the number of common tangents to th...

Find the number of common tangents to the circles `x^(2)+y^(2)-8x+2y+8=0andx^(2)+y^(2)-2x-6y-15=0`.

Verified by Experts

The correct Answer is:

Hence, the two circles intersect at two distinct points. Therefore, two tangents can be drawn.

Similar Questions

Explore conceptually related problems

The number of common tangents to the circles x^(2)+y^(2)-y=0 and x^(2)+y^(2)+y=0 is

The number of common tangents to the circles x^(2)+y^(2)-x=0 and x^(2)+y^(2)+x=0 , is

The number of common tangents to the circles x^(2) + y^(2) = 4 and x^(2) +y^(2) - 6x - 8y -24 =0 is,

Number of common tangents to the circles : x^2+y^2 -6x-14y+48=0 and x^2+y^2-6x=0 is :

The number of common tangents to the circles x^2+y^2-4x-6y-12=0 and x^2+y^2+6x+18y+26=0 , is :

The number of common tangents to the circles: x^2+y^2=4 , x^2+y^2 -4x +2y-4=0 is :

Find the number of common tangents that can be drawn to the circles x^2+y^2-4x-6y-3=0 and x^2+y^2+2x+2y+1=0

The number of common tangtnts that can be drawn to the circleS x^(2)+y^(2)=1 and x^(2)+y^(2)-2 x-6 y+6=0 is

The two circles x^(2) + y^(2) -2x + 6y + 6 = 0 and x^(2) + y^(2) -5x + 6y + 15 = 0