Show that the circles x^(2)+y^(2)-6x+4...

Show that the circles
`x^(2)+y^(2)-6x+4y+4=0and x^(2)+y^(2)+x+4y+1=0` cut orthogonally.

Verified by Experts

The correct Answer is:

Hence, the given circles cut each other orthogonally.

Similar Questions

Explore conceptually related problems

The circle x^(2)+y^(2)-8 x+4 y+4=0

If the circles x^(2)+y^(2)-2 x-2 y-7=0 and x^(2)+y^(2)+4 x+2 y+k=0 cut orthogonally, then the length of the common chord of the circles is

The value of k so that x^(2)+y^(2)+kx + 4y+ 2=0 and 2(x^(2) + y^(2)) - 4x - 3y + k = 0 cut orthogonally is

Prove that the circles x^(2) +y^(2) - 4x + 6y + 8 = 0 and x^(2) + y^(2) - 10x - 6y + 14 = 0 touch at the point (3,-1)

The locus of the centre of circle which cuts the circles x^2 + y^2 + 4x - 6y + 9 =0 and x^2 + y^2 - 4x + 6y + 4 =0 orthogonally is

Given that the circle x^(2)+y^(2)+2 x-4 y+4=0 and x^(2)+y^(2)-2 x-4 y-4=0 touch each other the equation of the common tangtnt is

The area of the circle x^(2)+y^(2)-2 x+4 y-4=0 is

The circles x^2+y^2+4x+6y+3=0 and 2(x^2+y^2)+6x+4y+c=0 will cut orthogonally if c is :

For the circles x^(2) + y^(2) - 2x + 3y + k = 0 and x^(2) + y^(2) + 8x - 6y - 7 = 0 to cut each other orthogonally the value of k must be