Home
Class 12
MATHS
The equation of the tangent to the circl...

The equation of the tangent to the circle `x^2 + y^2` + 4x - 4y + 4 = 0 which makes equal intercepts on the positive coordinate axes is:

A

x+y=2

B

`x+y=2sqrt2`

C

x+y=4

D

x+y=8

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The equations of the two tangents from (-5 , -4) to the circle x^(2) + y^(2) + 4x + 6y + 8 = 0 are

The circle x^(2) + y^(2)- 8x + 4y + 4=0 touches

The circle x^2 + y^2+ 4x-7y + 12 = 0 cuts an intercept on y-axis equal to

The length of the tangent from (5, 1) to the circle x^2+y^2+6x-4y-3=0 is :

The equation of the normal to the circle x^(2)+y^(2)+6 x+4 y-3=0 at (1,-2) is

The equation of the chord of the circle x^2 + y^2 - 4x = 0 , whose mid-point is (1, 0) is :

Find the equations of the tangents to the circle x^(2) + y^(2)=16 drawn from the point (1,4).

The equation of the common tangent to the parabolas y^(2)=4 x and x^(2)=4 y is

The equation of the common tangent of the curves x^(2)+4y^(2)=8 and y^(2)=4x is :

The equation of the tangent to the curve y^(2)=4ax at the point (at^(2), 2at) is :