Two circles x^2+y^2=6 and x^2+y^2-6x+8=0...

Two circles `x^2+y^2=6` and `x^2+y^2-6x+8=0` are given. Then the equation of the circle through their points of intersection and the point (1, 1) is :

A

`x^(2)+y^(2)-6x+4=0`

B

`x^(2)+y^(2)-3x+1=0`

C

`x^(2)+y^(2)-4x+2=0`

D

`x^(2)+y^(2)-2x+1=0`

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The correct Answer is:

B

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