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The point diametrically opposite to the ...

The point diametrically opposite to the point P (1, 0) on the circle `x^2+y^2+2x+4y-3=0` is :

A

(3,-4)

B

(-3,4)

C

(-3,-4)

D

(3,4)

Text Solution

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The correct Answer is:
C
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