solve for x. `(4)/(x+1)le3le (6)/(x+1),(xgt0)`

Solve -5 le (5-3x)/(2) le 8 .

solve |x-1|le3 ,

solve |x-1|le2 .

Solve (3(x-2))/(5) le (5(2-x))/(3)

Solve (5-2x)/(3) le (x)/(6)-5.

f(x) = (sqrt(1+px) - sqrt(1 - px))/(x), -1 le x le 0 = (2x + 1)/(x-2), 0 le x le 1 is continuous in the interval [-1, 1], then p is :

Show that the function f defined as follows, is continuoius at x=2, but not differentiable at x=2. f(x)={{:(3x-2, 0 lt x le 1),(2x^(2)-x, 1 lt x le 2),(5x-4,x gt 2):} .

Solve (5-2x)/(3) le x/6-10

Solution set of (|x-4|)/(x-4) le 0 is