int (dx)/((x+1)(x-2))=A log (x+1)+B log ...

`int (dx)/((x+1)(x-2))=A log (x+1)+B log (x-2)+C`, where

A

`A+B=0`

B

`AB=0`

C

`A//B=-1`

D

None of these

Verified by Experts

The correct Answer is:

A, C

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