If int(1)/((x^2+1)(x^2+4))dx=a tan^(-1)....

If `int(1)/((x^2+1)(x^2+4))dx=a tan^(-1). x+b tan^(-1).(x)/(2)+c`, then :

A

A=1/3

B

A= -1/3

C

B= 1/6

D

B= -1/6

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The correct Answer is:

A, D

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