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Calculate the length of an aluminium wir...

Calculate the length of an aluminium wire of diameter 0.5 mm required to have a resistance of3`Omega` at `20^(@)C` .Rresisitvity of aluminium is `2.8xx10^(-8)Omegam`

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R=3, `r=0.25xx10^(-3)m, " "p=2.8xx10_(-8)Omegam`
Resistivity`P=(RA)/(l)=(Rpir^(2))/(l)`
`thereforel=(Rpir^(2))/(p)=(3xx3.14xx(0.25xx10^(-3))^(2))/(2.8xx10^(-8)) " " l=21.03m`
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