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Six lead acid secondaryt celle each ofe...

Six lead acid secondaryt celle each ofemf 2Vand-internal resistanee 0.015`Omega` joined in series to provide a supply to a resistance of 8.5`Omega`. Find the current drawn from the battery and its terminal voltage.

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Data supplied,
E=2V, n=6, r=0.015 `Omega`, R=8.5`Omega`
`I=(nE)/(R+nr)=(6xx2)/((8.5+0.015xx6))=1.39A`
Terminal Voltage `=IxxR=1.39xx8.5=11.815V`
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