At room temperature `(27.0^(@)C)` the resistance of a heating element is 100`Omega`. What is the temperature of the element if the resistance is found to be 117`Omega`. Given that the temperature coefficient of the material of the resistor is `1.70 xx 10-4 ^@C.`

Explanation

`R_(1) = (230V)/(3.2A) = 71 .88 Omega " " R_(2) = (230V)/(2.8A) = 82.14 Omega`
`alpha = 1.7 xx 10 ^(-4) ""^(@)C^(-1) , T_(1) = 27^@C " "R_(2) = R_(1) (1 + alpha. Delta )`
`Delta T= (R_1 - R_1)/(R_1 alpha) = (82.14 -71.88)/(71.88 xx 1.7 xx 10^(-4)) = 840^(@)C`
`T_(2) = T_(1) Delta T = 27 + 840 = 867^(@)`C