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A train was moving at the rate of 54kmh^...

A train was moving at the rate of `54kmh^(-1)` when brakes were applied. It came to rest within a distance of 225 m. Calculate the retardation produced in the train.

Text Solution

Verified by Experts

The final velocity of the particle v = 0
The initial velocity of the particle
`u=54xx(5)/(18)ms^(-1)=15ms^(-1)`
`S=225m`
Retardation is always against the velocity of the particle.
`v^(2)=u^(2)-2aS`
`0=(15)^(2)-2a(225)`
`450a=225`
`a=(225)/(450)ms^(-1)=0.5ms^(-2)`
Hence, retardation `=0.5ms^(-2)`
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