Calculate the average velocity of the particle whose position vector changes from `vec(r_(1))=5hati+6hatj" to "vec(r_(2))=2hati+3hatj` in a tine 5 second.

Answer

Given: Position vectors of a particle
`vecr_(1)=5hati+6hatj,vecr_(2)=2hati+3hatj` time (t) =5s

Explanation

Average velocity: `vecV_(avg)=(Deltar)/(Deltat)=(vecr_(2)-vecr_(1))/(dt)=((2-5)hati+(3-6)hatj)/(5)`
`vecV_(avg)=(-3hati-3hatj)/(5)=(-3)/(5)(hati+hatj)`