An object at an angle such that the horizontal range is 4 time of the maximum height. What is the angle of projection of the object?

Answer

Given: Horizontal range `=4H_(max)`

Explanation

Horizontal range `=(u^(2)sin2theta)/(g)=(2u^(2)sinthetacostheta)/(g)`
Maximum height `=(u^(2)sin^(2)theta)/(2g)`
as given `(2u^(2)sinthetacostheta)/(g)=(4u^(2)sin^(2)theta)/(2g)`
`2costheta=2sintheta`
`tantheta=1`
`:.theta=45^(@)`