An object is thrown with initial speed `5ms^(-1)` with an angle of projection `30^(@)`. What is the maximum height and range reached by the particle?

Answer

Given: Initial speed `(u)=5ms^(-1)`
Angle of projection `theta=30^(@)`

Explanation

Max height reached `(H_(max))=(u^(2)sin^(2)theta)/(2g)=(25xx((1)/(2))^(2))/(2xx9.8)=0.318m`
Range `(R)=(u^(2)sin2theta)/(g)=(25xxsin60^(@))/(9.8)=2.21m`