If an object is thrown horizontally with an initial speed `"10 ms"^(-1)` from the top of a building of height 100 m. What is the horizontal distance covered by the particle.

Answer

Given: Initial speed `=10ms^(-1)`
Height of the building (h) = 100 m
Range =?

Explanation

Range of the object `=R=usqrt((2h)/(g))=10sqrt((200)/(9.8))=45.1m,`
R=45m